06.17.08
Project Euler: Problem 13
Work out the first ten digits of the sum of the following one-hundred 50-digit numbers.
37107287533902102798797998220837590246510135740250
46376937677490009712648124896970078050417018260538
74324986199524741059474233309513058123726617309629
91942213363574161572522430563301811072406154908250
…
20849603980134001723930671666823555245252804609722
53503534226472524250874054075591789781264330331690
A solution:
Copy the list of numbers and save them in a text file (here, Euler13number.txt). Then things are pretty easy, thanks to Python’s magic handling of large numbers.
file = open('Euler13number.txt', 'r')
a = [int(line) for line in file]
b = str(sum(a))
print b[:10]
file.close()
Or, for an even more condensed version:
file = open('Euler13number.txt', 'r')
print str(sum([int(line) for line in file]))[:10]
file.close()
